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Azimuth and Declination formulae

From: Peter Fogg (no email)
Date: Thu Jul 14 2005 - 20:29:19 EDT

  • Next message: Fred Hebard: "Re: Azimuth and Declination formulae"

    Peter Fogg wrote: (I did!)

    > Have found this one: (Azimuth formula)
    >
    > Chuck Pettis' Azimuth equation:
    > AZ = acos ((sin D - (sin L * sin H) / (COs L * COs H))
    > where H = horizon height (degrees)
    >
    > (The H has me puzzled. Perhaps it refers to Dip, or could it refer to
    > altitude?)
    >
    > Here's another:
    >
    > Z = cos^-1 * [sin Dec - sin Lat * sin h / cos Lat * cos h]
    > where h = vertical angle to the sun corrected for parallax and refraction
    > (h = altitude?)

    I think they are the same sine method.

    The first version may be for terrestrial navigators, with its added factor
    of 'horizon height'.

    Along the way, I found a formula for the calculation of the Sun's
    declination:

    Dec = 23.45 sin (360/365.25)
    Its such a simple formula even I can understand it. Its the maximum
    declination of the sun expressed as a proportion of its change.

    Here's another version:

    Dec/23.45 = sin(0.985*t)

    0.985 is a truncated version of (360/365.25)
    and t = the number of days from the vernal equinox
    or
    t = (inv sin(Dec/23.45))/(360/365.25)

    These formulae come from:
    www.geomancy/org./sunfinder


  • Next message: Fred Hebard: "Re: Azimuth and Declination formulae"



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