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From: Peter Fogg (no email)
Date: Sun Jul 10 2005 - 20:30:43 EDT
> From: george huxtable
> But Peter makes it difficult (indeed impossible) for anyone else to
> reproduce his calculation, by omitting mention of the values of hour-
> angle,
> lat, and dec that he has used. If Peter will provide that missing-link, he
> might get some more informed responses.
Here we go:
>The first comes from the problem Mike Burkes
>posed, that I worked out and posted here on the 2 July.
>
>Sun UL Azimuth - in decimal form, and to 3 decimal places if available
>101 'Bennett book' azimuth tables
>100.9 Sharp nav. calculator
>100.982 NavPac, given as 100d 58.9'
>100.985 Z tan formula
287d 02' LHA
N36d 00' lat
S00d 57' dec
13d alt
I think I've been able to answer my own question. NavPac (and the nav.
calculator) use internally generated values of declination and Local Hour
Angle (dec S00d 56.7', LHA 287d 02.1' for NavPac) which could explain the
small discrepancy. Substituting these values in the Z tan formula gives an
azimuth of 100.9810198d, or 100d 58' 51.6". The answer quoted above of 100d
58.9' could simply be the same answer rounded slightly.
Nevertheless, am interested in finding other formulas for the calculation of
azimuth for comparison.
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