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Resolving azimuth ambiguity - sometimes relatively simple

From: Noyce, Bill (no email)
Date: Tue May 31 2005 - 11:33:56 EDT

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    George Huxtable writes:
    > A simple and popular, but VERY faulty, method for calculating az. is-
    >
    > sin az. = sec Hc sin (dlong) cos dec.
    >
    > The serious problem with this is that sin 95 deg (say) is exactly the
    same
    > as sin 85 deg, and there is NO SIMPLE WAY to tell whether an azimuth,
    near
    > to East, should be North of East or South of East. This vital matter
    is
    > glossed-over in many texts.

    This is indeed a problem in many methods. But if you're using Ageton's
    method (is this HO211?) one of the intermediate results is the latitude
    at which a perpendicular to the body crosses your meridian. If this
    point is north of you, the azimuth has a northerly component; if it's
    south of you, the azimuth has a southerly component. (This rule has to
    be modified when the hour angle is not in the range -90..90, but I think
    the azimuth for a visible body is always toward your local pole in that
    case.)

    The other problem with this formula is that the sin changes slowly near
    due
    east or west, so if your AP was way out, the error in the LOP's angle
    could lead to a poor fix. At least with Ageton's method, it's possible
    to
    use your new fix as an AP and iterate, to see whether this is a serious
    issue.

            -- Bill


  • Next message: Victor Garand: "Re: A calendar question"



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