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Re: Precomputed lunar distances

From: Bill (no email)
Date: Mon Apr 18 2005 - 20:10:58 EDT

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    > Bill you wrote:
    > "Two sides of a spherical triangle meeting at the
    > zenith. Both start off almost perpendicular to the horizon and progressively
    > arc in to the zenith. So from the *observers* frame of reference,
    > refraction is acting up and in, less up and more in the higher the bodies."

    Frank replied:
    > I have a hunch that you're picturing a sort of "perspective drawing" of a
    > spherical triangle in which it might appear as if the refraction is acting
    > "in"
    > or sideways.

    Frank

    Yes, that is my image. A two-dimensional representation of three
    dimensions. What a camera would see.

    > It's important to picture a spherical triangle from the
    > perspective of the observer. The arcs (sides) of a spherical triangle are not
    > curved. If you draw a spherical triangle with corners at the zenith and two
    > arbitrary stars, all three sides look *exactly* straight as seen by the
    > observer.
    > Gou outside tonight and point at Spica. Now trace the side of the spherical
    > triangle that connects Spica to the zenith. You finger should trace a line
    > across the sky that looks (to you) exactly straight and exactly vertical.
    > Next
    > point at Antares. Trace the side of the triangle from Antares to the zenith.
    > Your arm should rise straight and vertical. Finally trace the side from
    > Antares
    > to Spica. Your finger should move straight across the sky. How does
    > refraction affect these triangle sides?? It lifts each star entirely
    > vertically and so
    > entirely within the two sides that lead to the zenith. There's no component
    > perpendicular to those sides. Make sense?? And of course, the distance
    > between the stars is reduced by refraction even through the refraction is
    > completely in the vertical direction.

    Understood. While there are no "straight" lines on the surface of a sphere,
    if the segment of the great circle is on the axis the eye is directed
    toward, it will appear to the observer as a straight line. The sextant has
    the ability to look in two directions at once--two straight lines. Now if I
    used a finger for each body and looked between them while tracing both the
    great circle segments to the zenith, would I still observe two straight
    lines? In any case a triangle is formed.

    What deeply confuses me is as follows. Using two hypothetical stars with
    equal declinations and an LHA between them, I calculate true separation as
    34d 27.7'. I raise the equal Hc's of the two stars from a staring point of
    1d 36.8' in increments of 11d 02.9' (11d 02.8 for last step) and calculate
    refraction separation correction. The results are as follows:

    Hc Refraction Correction
    1d 36.8' -18.2' -0.31796
    12d 39.7' -4.1' -0.57133
    23d 42.6' -2.2' -0.59930
    34d 45.5' -1.4' -0.60260
    45d 48.4' -0.9' -0.57422
    56d 52.3' -0.7' -0.64021
    67d 54.2' -0.4' -0.64310
    78d 57.1' -0.2' -0.63534
    89d 59.9' 0 0

    They do not seem to reflect refraction moving along a straight line to me,
    where I might expect the corrections to be similar to a curve derived from
    refraction values at those altitudes.

    Another hypothetical scenario. If I take the same two stars, calculate true
    separation of 34d 27.7', they have identical Hc's of 1d 36.8', and
    hypothetical refraction is -88d, what separation might I expect to measure
    with a sextant?

    Thanks for your continuing help,

    Bill


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