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Re: Proportional logs, etc.

From: Frank Reed (no email)
Date: Thu Aug 26 2004 - 19:35:43 EDT

  • Next message: Bruce Stark: "Re: Proportional logs, etc."

    Henry H wrote:
    "how to calculate these logs, please give me a shout. These things seem to
    have passed into antiquity without so much as an obituary, as respects
    navigation"

    In case it hasn't been said yet in this discussion, the definition of normal
    proportional logs is simply
       P.L.(x) = log(3/x)
    which is of course equivalent to log(3) - log(x) so the lack of a
    proportional log table saves only a single subtraction. Because the practice of lunars
    invariably involved interpolation between two predicted lunar distances
    separated by three hours, saving a subtraction here and there added up in the long
    term.

    By the way, if x is in seconds (or time or arc), then the "3" will be
    replaced by 3*3600 or 10800. So as an example, the proportional log of 500 seconds
    should be given by
      P.L.(500") = log(10800") - log(500") = 1.33445.

    Because proportional logs are a sort of "upside-down" logarithm, converting a
    modern calculation to proportional logs generally involves inverting it. For
    example, if I want to calculate the Moon's parallax, I would calculate
      p = HP*cos(h).
    Converting to ordinary logarithms this would be
      log(p) = log(HP) + logcos(h)
    but with proportional log tables the calculation would be
      PL(p) = PL(HP) + logsec(h).

    Frank R
    [ ] Mystic, Connecticut
    [X] Chicago, Illinois


  • Next message: Bruce Stark: "Re: Proportional logs, etc."



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