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Subject: Re: Wind & Current Navigation
From: David Weilacher (daveweilacher@XXX.XXX)
Date: Thu Apr 17 2003 - 08:21:28 EDT
...so would a 2 knot current be the sqrt((2^2) * 830) = 58kt wind?
-------Original Message-------
From: George Huxtable <george@XXX.XXX>
Sent: 04/17/03 10:16 AM
To: NAVIGATION-L@XXX.XXX
Subject: Re: Wind & Current Navigation
At the same rate of flow, the water force would be about 830 times
greater,
because water is denser than air by that factor. The force will vary as
the
square of the velocity, so the force due to a 1 knot tide on the buoy
would
be equivalent to the force of a breeze of nearly 30 knots (28 being the
square root of 830, roughly). That gives an idea of the order-of-magnitude
of differences between water forces and wind forces.
Dave Weilacher
.US Coast Guard licensed captain
. #889968
.ASA instructor evaluator and celestial
. navigation instructor #990800
.IBM AS400 RPG contract programmer
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