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Subject: Re: Q: how to calculate refraction at higher altitudes on land?
From: Dan Allen (danallen46@XXX.XXX)
Date: Thu Feb 28 2002 - 18:23:01 EST
Great ideas all! I'll have to do the barometer experiment (the ocean
is less than an hour away), and I'll also mess around with measuring
the angle to the top of Rattlesnake Ridge, the mountain south of my
house.
Dan
-----Original Message-----
From: Navigation Mailing List
[mailto:NAVIGATION-L@XXX.XXX]On Behalf Of Craig
Sent: Thursday, February 28, 2002 12:41 PM
To: NAVIGATION-L@XXX.XXX
Subject: Re: Q: how to calculate refraction at higher altitudes on land?
I was thinking, in using trigonometry to solve a right triangle, you know
the adjacent side from your GPS (Difference between your lat/lon position
and lat/lon of mountain peak. You measure the angle, can get the tangent,
and solve for the opposite side, which is the difference between height of
mountain peak and your height. Subtract length of oppposite side from
mountain peak height, doesn't that give you your height?
Tangent=opposite/adjacent, therefore opposite=tangent*adjacent.
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