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Subject: Re: Relative plotting vs Geographical plotting
From: George Huxtable (george@XXX.XXX)
Date: Sat Jan 12 2002 - 03:37:31 EST
Peter Smith wrote-
>George Huxtable [mailto:george@XXX.XXX] said:
>>
>> I don't think Peter Smith's solution can possibly be correct: commonsense
>> tells me so. We have two ships travelling in nearly the same direction,
>and
>> the second ship is slowly overtaking the first. In that case, the speed of
>> the overtaking ship must be greater than that of the ship being overtaken.
>
>Hmmm. I'm not sure from the above who's the "second ship" and who's
>the "first ship". The target is ahead of us and to Port (bearing 322d).
>The bearing is constant, so we are converging. Since the target is
>ahead and the range is decreasing, we must be overtaking the target.
>
>> ...
>> If you add the vectors 12 knots at 150 and 1.45 knots at 142, using trig
>or
>> drawing, you end up with 13.44 knots at 149.1.
>
>But that gives the target a greater speed than our own ship, even
>though we are overtaking it.
>
>Moreover, the target is on our Port bow (bearing 322d). For our
>courses to converge (constant bearing), the target's course must
>be a little to starboard (i.e., numerically GREATER) of ours. Thus,
>if we're making 150d, he should be making a little greater then 150d.
>If he's making 149.1d, we would be diverging.
>
>Can you read an Excel spreadsheet? I have both the geographic and
>relative vectors problems worked out trigonometrically. I'll send
>it to you and see what you think.
>
> -- Peter
=================
George Huxtable replies-
Aha! The penny drops... Now I see why we disagree. I didn't read Pierre
Boucher's problem fully. Here is what he said-
===================
>Own course and speed:
>150d 12.0 kt
>
>On the radar screen (relative bearing mode):
>at 0448 a "spot" at 7.0 nm 322d on the screen
>at 0554 a "spot" at 5.4 nm 322d on the screen
>
>Request :
>Other ship's course
>Other ship's speed
===================
Pierre states quite clearly "relative bearing mode". For some reason, I
took it as North-up mode instead. It makes all the difference, of course. I
was quite wrong. Sorry about that.
When I repeat the calculation, summing vectors, I now get exactly the same
result as Peter Smith, 10.9 knots at 154.7 degrees.
Thanks for putting me right, Peter.
George Huxtable.
------------------------------
george@XXX.XXX
George Huxtable, 1 Sandy Lane, Southmoor, Abingdon, Oxon OX13 5HX, UK.
Tel. 01865 820222 or (int.) +44 1865 820222.
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