leg 60
Subject: leg 60
From: R. Winchurch (rawinch@XXX.XXX)
Date: Thu Mar 23 2000 - 09:25:52 EST
# 2. Distance 88.5 nm
# 3. 190d t
But I cheated and I am somewhat confused by my answers. I used a
program entered into my TI 60 calculator for determining Hc and Z. I
computed lha by the difference between my lat and the long. of the
waypoint. I entered my lat and substituting the lat for the waypoint
for dec in the program.
Then I checked my calculations using the Nav20 program in the archive.
My question is this. The program calculates Hc which is in degrees
between the assumed position and the gp of the body (in this case it
would be the waypoint. Since 1 degree equals 60 nm the calculated
distance should have been 60 X the degrees arrived at from the
calculation or 5310 nm. How did Nav 20 come up with 88.5 nm?
