Next message: Beau Vrolyk: "RE: lv-ab: Combining Bilge pump discharges"
I beg to differ. You are correct in that Ohm's law applies. But you have to consider which in the equation are constant and which are variable. The variation of Ohm's law that would apply is P=IV where V is obviously variable and P, the power requirement of the device is more or less constant. That says that I (current) will vary relative to voltage. This is visible to me as my batteries discharge and the fridge, say, is running. With a full charge showing something in the neighbourhood of 13V, it draws 9.2A. When my voltage has dropped to 12 volts (at around 50-60% discharged), its drawing over 10. Having said all that, there are several other variables that come into play such as is the load purely resistive etc, but in general, the current use does increase.
Regards....Randy
----- Original Message -----
From: <>
To: <>; <>
Sent: August 20, 1999 11:09
Subject: Re: lv-ab: Battery Charging: How Charge Large House Bank?
> In a message dated 8/20/1999 1:26:41 PM Eastern Daylight Time,
> writes:
>
> > because to supply, say 60w, takes only 5A at 12v, but takes 5.22A at 11.5v.
>
> What you have stated is true, but, in the real world, the power (W)
> requirement doesn't remain constant. A load will draw less current when
> operated at less than design voltage. (Ohm's law: I = E/R )
>
> John
> Truelove
>
>
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